Why is the following program incorrect given that the user wants print$($b$)$ to display:

$[4,5,[1,2,3]]$

a $=[1,2,3]$

b $=[4,5,$ a $]$

a$[1]=\text{'}$d$\text{'}$

print$($b$)$

Python

$b=[4,5,a]$ is a copy of list a$.$ In other words, list b only contains a copy to list a$.$

Any changes to list a will be reflected in list $b$ since b$\text{'}$s entry for list $a$ is a copy of

the original list.

$b=[4,5,a]$ uses a pointer to reference the list $a.$ In other words, list b only contains

a pointer to list $a.$ Any changes to list a will be reflected in list $b$ since b$\text{'}$s entry

for list a points to the original list.

This is impossible. There does not exist a programming technique, in Python, to

do what the programmers wants to accomplish.