Question: why is this now true after converting Ax=b using digonal dominsnce? The problem states that the equation Ax=bAx=b can be expressed as x=T(x)x=T(x) where the

why is this now true after converting Ax=b using digonal dominsnce? The problem states that the equation Ax=bAx=b can be expressed as x=T(x)x=T(x) where the operator T:RnRnT:RnRn is defined by T(x)=(IA)x+b T(x)=(IA)x+b where II is the identity matrix

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