With the clock circuit running, you can now make some useful digital circuit measurements.

The $555$ timer oscillator circuit has a Period T of

$T=0\mathrm{.}695(RA+2RB)C($ seconds $)=$

$$

The $555$ timer oscillator frequency is related to the period by

$F=\frac{1}{T}(Hz)=$

$$

The $555$ timer oscillator circuit has an On time of

$T=0\mathrm{.}695(RA+RB)C($ seconds$)=$

$$

The $555$ timer oscillator circuit has a Duty Cycle $($On time$/$period$)$ of

$DC=\frac{RA+RB}{RA+2RB}=$

$$