with the given data analysis can u answer the question please

3. Blue dextran has a MW of about 2 million, and its molecules are too large to enter the porous beads of Sephadex. Suppose there were another marker molecule called "red dextran," with a MW of 5 million. How do you think the elution volume for "red dextran" would compare with that of blue dextran? Explain your answer. Data analysis The fraction with the most concentrated blue dextran represents the void volume of the column--the amount of liquid between the gel beads. Thus, if the maximum amount of blue dextran was eluted in the sixth tube, the void volume (Vo) would be 6 x 2.0 mL = 12 mL. Determine the elution volume (Ve) for each of the remaining macromolecules, and then determine each molecule's partition coefficient, Kav, from the following formula: Kav = (Ve-V0)/(Vt - Vo), where Vt is the total column volume (60mL), and Vo and Ve are defined above. Vo and Vt are properties of the column and will be the same for each peak, but each peak will have its own Ve. For blue dextran, Ve=Vo. Unless a compound has a chemical affinity for Sephadex (which these should not), Ve should be no greater than Vt, so Kay should never be greater than 1 (nor less than 0). a