Would the contains() method of the lazy and lock-free algorithms still be correct if logically removed entries
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Would the contains() method of the lazy and lock-free algorithms still be correct if logically removed entries were not guaranteed to be sorted?
The add() method of the lock-free algorithm never finds a marked node with the same key. Can one modify the algorithm so that it will simply insert its new added object into the existing marked node with same key if such a node exists in the list, thus saving the need to insert a new node?
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