Question: Would you help me with solving those questions 1. Fall A What was the speed of puck A before the collision? On a frictionless, horizontal

Would you help me with solving those questions

1.

Would you help me with solving those questions 1.Would you help me with solving those questions 1.Would you help me with solving those questions 1.Would you help me with solving those questions 1.Would you help me with solving those questions 1.Would you help me with solving those questions 1.
Fall A What was the speed of puck A before the collision? On a frictionless, horizontal air table, puck A (with mass Express your answer in meters per second. 0.250 kg) is moving toward puck B (with mass 0.360 kg), that is initially at rest. After the collision, puck A has a velocity of 0.125 m/s to the left, and puck B has velocity 0.660 m/s to the v = 0.825 m/s right. Submit Previous Answers For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Collision along a straight line. V Correct IDENTIFY: Apply conservation of momentum to the system of the two pucks. SET UP: Let +x be to the right. EXECUTE: Pir = Par says (0.250 kg)VAI = (0.250 kg)(-0.125 m/s) + (0.360 kg) (0.660 m/s) and VAI = 0.825 m/s Part B Calculate the change in the total kinetic energy of the system that occurs during the collision. Express your answer in joules. AE AK =Correct IDENTIFY: a = m dt Dex dm Assume that dm/ dt is constant over the 5.0 s interval, since m doesn't change much during that interval. The thrust is dm A 70 kg astronaut floating in space in a 110 kg MMU (manned F = -Vex dt maneuvering unit) experiences an acceleration of 0.029 m/s SET UP: Take m to have the constant value 110 kg + 70 kg = 180 kg. dm/dt is negative since the mass of the MMU decreases as gas is when he fires one of the MMU's thrusters. ejected. For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Acceleration of a rocket. EXECUTE: . dm 180 kg dt Vex 490 m/s (0.029 m/$2) = -0.0106 kg/s. In 5.0 s the mass that is ejected is (0.0106 kg/s) (5.0 s) = 0.053 kg. Part B What is the thrust of the thruster? HA F = Value UnitsExpress your answer in newton seconds. 0.535 N . S A steel ball with mass 45.0 g is dropped from a height of 2.08 m onto a horizontal steel slab. The ball rebounds to a height of 1.54 m. Submit Previous Answers Correct V Part B If the ball is in contact with the slab for a time of 1.60 ms, find the average force on the ball during impact. Express your answer in newtons. AED ? NV Part A For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Calculating angular velocity. What angle in radians is subtended by an arc of 1.53 m in length on the circumference of a circle of radius 2.40 m? Express your answer in radians. IVO AED 2 reset 0 = rad Submit Request Answer V Part B What is this angle in degrees? Express your answer in degrees. IVO ? 0 =Y Part C An arc of length 13.8 cm on the circumference of a circle subtends an angle of 127. What is the radius of the circle? Express your answer in centimeters. AED r = cm Submit Request Answer V Part D The angle between two radii of a circle with radius 1.57 m is 0.630 rad. What length of arc is intercepted on the circumference of the ci Express your answer in meters. VO AED ? m L =Part A A safety device brings the blade of a power mower from an initial angular speed of w1 to rest in 5.00 revolution. At the same constant acceleration, how many revolutions would it take the blade to come to rest from an initial angular speed w3 that was three times as great, For related problem-solving tips and strategies, you may want to W3 = 3w1? view a Video Tutor Solution of Rotation with constant angular acceleration. ? n=

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