Write a c$++$a beginning class program that takes a positive odd number as input and outputs the following. You may assume that you always enter positive odd numbers correctly. result should look like an hourglass with zeros on the empty space like in output examples. in my code is there another without using arrays, vectors or private classes

#include

#include $//$ For setw

using namespace std;

class Hourglass $\{$

private:

int size;

int arr$[100][100]$; $//$ Assuming a maximum size of $100$ for the hourglass pattern

$//$ Helper function to fill the hourglass pattern

void fillHourglass$()\{$

$//$ Reset all elements of the array to $0$

for$($int i $=0$; i $$ size; $++$i$)\{$

for$($int j $=0$; j $$ size; $++$j$)\{$

arr$[$i$][$j$]=0$;

$\}$

$\}$

int number $=1$;

int start $=0,$ end $=$ size $-1$;

for$($int i $=0$; i $$ size; $++$i$)\{$

for$($int j $=$ start; j end; $++$j$)\{$

arr$[$i$][$j$]=$ number$++$;

$\}$

if$($i $$ size$/2)\{$

start$++$;

end$--$;

$\}$ else $\{$

start$--$;

end$++$;

$\}$

$\}$

$\}$

$//$ Helper function to find the width needed for formatting

int getWidth$()\{$

int max$\_$num $=$ size $*$ size;

int width $=0$;

while$($max$\_$num $>0)\{$

max$\_$num $/=10$;

width$++$;

$\}$

return width;

$\}$

public:

$//$ Constructor to initialize the size of the hourglass

Hourglass$($int s$)$ : size$($s$)\{\}$

$//$ Function to print the hourglass pattern

void print$()\{$

fillHourglass$()$;

int width $=$ getWidth$()$;

$//$ Print the hourglass pattern with appropriate width

for$($int i $=0$; i $$ size; $++$i$)\{$

for$($int j $=0$; j $$ size; $++$j$)\{$

cout $$ setw$($width$)$ arr$[$i$][$j; $//$ Print numbers with setw

$\}$

cout $$ endl; $//$ Move to the next line after printing a row

$\}$

$\}$

$\}$;

int main$()\{$

char choice;

do $\{$

int size;

cout

Enter size: $"$;

cin $>>$ size;

Hourglass hourglass$($size$)$; $//$ Create an instance of the Hourglass class with the given size

hourglass.print$()$; $//$ Call the print function to print the hourglass pattern

cout

More $($y$/$n$)?"$;

cin $>>$ choice;

$\}$ while$($choice $==\text{'}$y$\text{'}||$ choice $==\text{'}$Y$\text{'})$;

return $0$;

$\}$