Write a C++ program that simulates the casino game of craps. These are the rules of the game: If a player throws a 7 or 11 (sum of two dice) the player wins the game. If a player throws a 2, 3 or 12 (sum of two dice) the player loses the game. If a player throws a 4, 5, 6, 8, 9 or 10 (sum of two dice) on the first roll, s(he) neither wins nor loses but creates a point. If this is the case, the player keeps rolling the dice until the point (4, 5, 6, 8, 9 or 10) is being rolled again, and the player wins the game. However, if the player throws a 7 (sum of two dice) before the point is thrown, the player loses the game. Create trials of 10000 times and what is the percentage (in decimals) of you winning. I already asked this question but got an incomplete answer. I tried to do it myself but got an error.

#include #include using namespace std;

int main()

{

const int TRIALS = 10000;

int dice1, dice2, sum, point, wins = 0, lose = 0;

srand(time(0));

for (int i = 1; i <= TRIALS; i++)

{

dice1 = rand() % 6 + 1;

dice2 = rand() % 6 + 1;

if ((dice1 + dice2) == 7 || (dice1 + dice2) == 11) {

wins++;

}

else if ((dice1 + dice2) == 2 || (dice1 + dice2) == 3 || (dice1 + dice2) == 12) {

lose++;

}

else if (dice1 + dice2 == 4 || dice1 + dice2 == 5 || dice1 + dice2 == 6 || dice1 + dice2 == 8 || dice1 + dice2 == 9 || dice1 + dice2 == 10)

{

dice1 = rand() % 6 + 1;

dice2 = rand() % 6 + 1;

if (dice1 + dice2)

{

wins++;

}

else if (dice1 + dice2 == 7)

{

lose++;

}

}

cout << "The number of times you have played is" << TRIALS << "times, and you won" << wins << "times, and you lost" << lose << "times. The percentage of winning is" << (wins * 1.0 / TRIALS) << endl;

return 0;

}

After debugging it should be something like: The number of times you have played is 10000 times, and you won 49## times, and you lost 50## times. //The total number of win&lose times should add up to 10000 The percentage of winning is 0.491673

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