Write a class called CommonElements with a single method main that will:

Create and obtain two integer arrays (arrayA and arrayB) using RandomIntegerArrayCreator type objects and its methods, find the number of common elements between arrayA and arrayB (say: if integer 2 appears in arrayA once and twice in arrayB, that counts as ONE common element between the two),

Constraints / notes: All array elements are integers from the the set {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10} and can appear multiple times in each array, Arrays A and B do NOT have to be of the same size, Arrays A and B CAN be empty (no elements), Arrays A and B will NOT be sorted.

The code that I have already created:

Transcribed Image Text:

import java.util.Random; public class RandomIntegerArrayCreator { int[] arr; RandomIntegerArrayCreator(){ Random rand = new Random(); int size - rand.nextInt (16); arr = new int[size]; for (int i=0;i<size;i++){ arr[i] rand.nextInt (11); public int getArraysize(){ return this.arr.length; public int[] getArray (){ return this.arr; public static void main(String[] args) { RandomIntegerArrayCreator r = new RandomIntegerArrayCreator (); System.out.println("Size = int[] arr = r.getArray(); System.out.print("Generated array is "); for (int i=0;i<arr.length;i++){ System.out.print (arr[i]+" "); "+r.getArraysize()); import java.util.Random; public class RandomIntegerArrayCreator { int[] arr; RandomIntegerArrayCreator(){ Random rand = new Random(); int size - rand.nextInt (16); arr = new int[size]; for (int i=0;i<size;i++){ arr[i] rand.nextInt (11); public int getArraysize(){ return this.arr.length; public int[] getArray (){ return this.arr; public static void main(String[] args) { RandomIntegerArrayCreator r = new RandomIntegerArrayCreator (); System.out.println("Size = int[] arr = r.getArray(); System.out.print("Generated array is "); for (int i=0;i<arr.length;i++){ System.out.print (arr[i]+" "); "+r.getArraysize());

Answer rating: 100% (QA)

arrA and arrB are 2 randomly generated arrays from r and ... View the full answer