Write a function called "myrweibull" to generate $n$ realizations from the Weibull distribution using

the probability integral transform method. The Weibull cdf is given by:

$(,|)=1-e^{-(\frac{x}{}{)}^{}}$;$x>0,>0,>0$

$($This is the parameterization I want you to use. Also note that the cdf is $0$ if $x0.)$

The function's name must be "myrweibull".

It must take the following arguments $($named as such$)$:

$n-$ The sample size; i$.$e$.$ the number of realizations to generate.

Include error checking to be sure that n is a numeric scalar and greater than or

equal to $1.$

If it is not an integer, then coerce into the nearest integer less than the value

given.

No default value.

shape $-$ This is the value of $.$ It is named "shape" because $$ is a shape parameter.

Include error checking to be sure that shape is a numeric scalar and greater than

$0.$

No default value.

scale $-$ This is the value of $.$ It is named scale because $$ is a scale parameter.

Include error checking to be sure that scale is a numeric scalar and greater than

$0.$

The default value is $1.$

It must return the vector of $n$ realizations from the desired Weibull distribution.

Additional details:

You may urite a function called "myrweibull" to generate $n$ realizations from the Weibull distribution using

the probability integral transform method. The Weibull cdf is given by:

$(,|)=1-e^{-(\frac{x}{}{)}^{}}$;$x>0,>0,>0$

$($This is the parameterization I want you to use. Also note that the cdf is $0$ if $x0.)$

The function's name must be "myrweibull".

It must take the following arguments $($named as such$)$:

$n-$ The sample size; i$.$e$.$ the number of realizations to generate.

Include error checking to be sure that n is a numeric scalar and greater than or

equal to $1.$

If it is not an integer, then coerce into the nearest integer less than the value

given.

No default value.

shape $-$ This is the value of $.$ It is named "shape" because $$ is a shape parameter.

Include error checking to be sure that shape is a numeric scalar and greater than

$0.$

No default value.

scale $-$ This is the value of $.$ It is named scale because $$ is a scale parameter.

Include error checking to be sure that scale is a numeric scalar and greater than

$0.$

The default value is $1.$

It must return the vector of n realizations from the desired Weibull distribution.

Additional details:

You may use the default R function "runif" to generate realizations from the $U(0,1)$

distribution, but do not use "rweibull", "qweibull", or any other built$-$in Weibull$-$related

functions.

Do not attempt to modify or set R$\text{'}$s seed value for random number generation.e probability integral transform method. The Weibull cdf is given by:

$(,|)=1-e^{-(\frac{x}{}{)}^{}}$;$x>0,>0,>0$

$($This is the parameterization I want you to use. Also note that the cdf is $0$ if $x0.)$

The function's name must be "myrweibull".

It must take the following arguments $($named as such$)$:

$n-$ The sample size; i$.$e$.$ the number of realizations to generate.

Include error checking to be sure that n is a numeric scalar and greater than or

equal to $1.$

If it is not an integer, then coerce into the nearest integer less than the value

given.

No default value.

shape $-$ This is the value of $.$ It is named "shape" because $$ is a shape parameter.

Include error checking to be sure that shape is a numeric scalar and greater than

$0.$

No default value.

scale $-$ This is the value of $.$ It is named scale because $$ is a scale parameter.

Include error checking to be sure that scale is a numeric scalar and greater than

$0.$

The default value is $1.$

It must return the vector of n realizations from the desired Weibull distribution.

Additional details:

You may use the default R function "runif" to generate realizations from the $U(0,1)$

distribution, but do not use "rweibull", "qweibull", or any other built$-$in Weibull$-$related

functions.

Do not attempt to modify or set R$\text{'}$s seed value for random number generation.