Write a function named is$\_$palindrome that accepts a string parameter and returns True if that string is a palindrome, or False if it is not a palindrome.

For this problem, a palindrome is defined as a string that contains exactly the same sequence of characters forwards as backwards, case$-$insensitively. For example, "madam" or "racecar" are palindromes, so the call of is$\_$palindrome$("$racecar$")$would return True. Spaces, punctuation, and any other characters should be treated the same as letters so a multi$-$word string such as "dog god" could be a palindrome, as could a gibberish string such as $"123$ $$ $321".$ The empty string and all one$-$character strings are palindromes by our definition. Your code should ignore case, so a string like "Madam" or "RACEcar" would also count as palindromes.

import string

def is$\_$palindrome$($s$)$:

s $=\text{'}\text{'}.$join$($c for c in s if c not in string.punctuation $+"")$

if len$($s$)==\backslash$varnothing:

return True

if len$($s$)==1$:

return True

return s $==$ s$[$::$-1]$

Attached is my code. I can't figure out how to pass the $11$th test.