Write a higher$-$order function twice that takes as a parameter a function of one argument and returns a function that represents the application of that function to its argument twice. Given theusual definition of the square function, what functioni s$($twice $($twice square$))?$ex$.$ If I write

$($define $($square x$)(*$ x x$))$ ; without lambda

I can call

$(($twice square$)3)$; returns $81-$ square applied to $3$ twice

$[$If you wish you may write twice with two parameters and call the function as:

$($twice square $3)$ ; this will also return $81]$