• Write a method named isMasonA() in java please explain each step. I would rate positively. Thanks.
• public static boolean isMasonA(int array[] that returns true if the array is MasonA false otherwise.
• Please make sure to get input through Scanner from user.
• Explaination:
• An array is called MasonA if it has the following properties: * - The value of the first element equals the sum of the next two elements, which is equals to the next three elements, equals to the sum of the next four elements, etc. * - It has a size of x*(x+1)/2 for some positive integer x . * * For example {6, 2, 4, 2, 2, 2, 1, 5, 0, 0} is MasonA, whereas {2, 1, 2, 3, 5, 6} is not */
• The value of the first element equals the sum of the next two elements, which equals to the next three elements, which equals to the sum of the next four elements, etc.
• for example:
• input array

{6, 2, 4, 2, 2, 2, 1, 5, 0, 0}

output

true (6=2+4=2+2+2=1+5+0+0)

input ={2, 1, 2, 3, 5, 6}

output = false (2 !=1+2 != 3+5+6)