Write a method that takes a single argument num, an integer, and prints the number passed in and whether it is even or odd. This method is named oddEvenChecker, and works as follows:

oddEvenChecker$(3)$; $//$ prints $"3$ is an odd number" oddEvenChecker$(8)$; $//$ prints $"8$ is an even number"

To do this exercise, it is helpful to know about the modulo operator, represented in Java by the symbol $\%.$ Modulo returns the remainder of the number in the right of it divided by the number to the left it $-$ so for example, the value of the expression $7\%3$ is $1($because $7$ divided by $3$ is $2$ with a remainder of $1).$

Implement another method, multipleOfChecker, that takes two arguments num and base, both integers. It then prints whether or not the first number is a multiple of the second number. For instance:

multipleOfChecker$(16,4)$; $//$ Should print $"16$ is a multiple of $4"$ multipleOfChecker$(11,3)$; $//$ Should print $"11$ is not a multiple of $3"$

Add at least $2$ additional tests to each method, which are DIFFERENT from the given tests. Test your methods in main using various combinations of inputs to rule out any logical bugs. Add the tests and comments with results$$ to the code before you submit!

Write a method named sqrtSumBucketer$,$ that asks the user to input two doubles. It sums their square roots, and prints a statement based on what bucket the result is in$.$ The possible buckets are "Less than $10",$ "Between $10$ and $20",$ "Between $20$ and $30",$ and "Greater than $30."$ Negative numbers should be rejected with the appropriate message printed to the user. To find a square root, use Math.sqrt$()($don$\text{'}$t forget to import java.lang.Math$).$

For example:

If user enters $23$ and $16,$ then the output should be

Less than $10$

If user enters $2$ and $999,$ then the output should be

Greater than $30$