Write a method that will return a string in the correct scientific notation given a precision parameter. The table below gives example input and output for the method. The input and output will both be strings. The precision will be an integer >= 0.

String - Value	Precision	Resulting String
------------------------------	--------------------	-------------------------
31536000	0	3E7
31536000	1	3.2E7
31536000	20	3.1536000E7 Not enough digits to have 20 places so only gives the answer with the greatest precision it can; in this case it is 7 places after the decimal.
-31536000	1	-3.2E7
3	Any value	3
0	Any value	0

public String covertSci(String number, int prec){

// precondition: prec >= 0

// postcondition: Returns a string that holds this number in

// scientific "calculator" notation with the

// prec number of digits. If prec >= NumDigits()

// it is reduced to the number of digits - 1.

This is what i have so far. I need help completing it.

1st class - Main.java

class Main{

public static void main(String[]args){

ScientificNot scinumber = new ScientificNot("31536000", 0);

System.out.println(scinumber);

}

2nd Class - ScientificNot.java

class ScientificNot{

char decimal '.';

String value;

int prec;

public ScientificNot(){

value = "";

prec = 0;

}

public ScientificNot (String value, int prec){

this.value = value;

this.prec = prec;

}

public String getValue(){

return value;

}

public ScientificNot convertSci(String value , int prec){

if (prec == 0){

value = (value.charAt(0) + "E" + value.substring(1,8).length());

if (prec == 1){

value = (value.charAt(0) + value.substring(0,1) + decimal + value.substring(1,2) + "E" + value.substring(2,8).length());

return value;

if (prec == 20){

value = (value.charAt(0)+ value.substring(0,1) + decimal + value.substring(1,2) + "E" + value.substring(2,8).length());

return value;

}

}

}

}

public String toString(){

return value + "," + prec;

}

}