Write a non-recursive Java application for the in-order traverse for a binary tree. Using stack.

I would like a different example from the way some google searches show the answer to be please!

1) Create an empty stack S. 2) Initialize current node as root 3) Push the current node to S and set current = current->left until current is NULL 4) If current is NULL and stack is not empty then a) Pop the top item from stack. b) Print the popped item, set current = popped_item->right c) Go to step 3. 5) If current is NULL and stack is empty then we are done. 

Let us consider the below tree for example

 1 / \ 2 3 / \ 4 5 Step 1 Creates an empty stack: S = NULL Step 2 sets current as address of root: current -> 1 Step 3 Pushes the current node and set current = current->left until current is NULL current -> 1 push 1: Stack S -> 1 current -> 2 push 2: Stack S -> 2, 1 current -> 4 push 4: Stack S -> 4, 2, 1 current = NULL Step 4 pops from S a) Pop 4: Stack S -> 2, 1 b) print "4" c) current = NULL /*right of 4 */ and go to step 3 Since current is NULL step 3 doesn't do anything. Step 4 pops again. a) Pop 2: Stack S -> 1 b) print "2" c) current -> 5/*right of 2 */ and go to step 3 Step 3 pushes 5 to stack and makes current NULL Stack S -> 5, 1 current = NULL Step 4 pops from S a) Pop 5: Stack S -> 1 b) print "5" c) current = NULL /*right of 5 */ and go to step 3 Since current is NULL step 3 doesn't do anything Step 4 pops again. a) Pop 1: Stack S -> NULL b) print "1" c) current -> 3 /*right of 5 */ Step 3 pushes 3 to stack and makes current NULL Stack S -> 3 current = NULL Step 4 pops from S a) Pop 3: Stack S -> NULL b) print "3" c) current = NULL /*right of 3 */ Traversal is done now as stack S is empty and current is NULL.