WRITE A PROGRAM IN FORTRAN THAT READS THE TWO MATRICES$(3\mathrm{.}3)$ AND $(3\mathrm{.}3)$B AND THEN DOES THE FOLLOWING:$-1-$ REPLACE THE ELEMENTS OF THE FIRST COLUMN IN THE MATRIX$(8)$ WITH THE ELEMENTS OF THE THIRD COLUMN OF THE MATRIX $($B$)2-$ THE SUM OF THE ELEMENTS OF THE MAIN DIAGONAL OF THE $13$MATRIX $($A$)$ IS CALCULATED AFTER SUBSTITUTION WI$3-$ THE MATRIX $($C$)$ IS FORMED FROM THE SUM OF THE TWO MATRICES $($A$)$ AND $($B$)$ AFTER SUBSTITUTION, MAKING ANY ELEMENT IN THE MATRIX $($C$)$ WHOSE VALUE IS LESS THAN $(10)$ EQUAL TO TWICE ITS VALUE.