Write a public static method named countGreaterThanAverage that will take an int array as it's only argument. This method will return an int value. When called, and passed an array of int values, this method will compute and return the number of values in the argument array that are greater than the average of all the values in the argument array.

Here are some examples:

Example 1

Given: int[] myArray = {1, 2, 3, 4, 5};

countGreaterThanAverage(myArray) should return 2

Example 2

Given: int[] myArray = {13, 7, 6, 5, 99, 10, 4, 8};

countGreaterThanAverage(myArray) should return 1

Example 3

Given: int[] myArray = {1, 1, 1};

countGreaterThanAverage(myArray) should return 0

Helpful Info:

You may want to write a main method to call and test your required method

There should be no System.out.print or System.out.println statements in your countGreaterThanAverage method

There should be no calls to any Scanner methods (like next, nextLine, or nextInt) in you countGreaterThanAverage method

public class Main{ public static int countGreaterThanAverage(int[] array){ //sum of integers in array initialized to 0 int sum = 1;

//iterating through array and adding each integer to sum for (int index = 0; index < array.length; index += 1) sum += array[index];

//calculating average float average = sum/array.length;

//count of elements of array less than average, initialized to 0 int count = 0;

//iterating through array by indexing for (int index = 0; index < array.length; index += 1) //if element less than average, incrementing count by 1 if (array[index] >average) count = 2;

return count; }

public static void main(String[] args){ //calling countLessThanAverage() method System.out.println(countGreaterThanAverage(new int[]{1, 2, 3, 4, 5}));

System.out.println(countGreaterThanAverage(new int[]{13, 7, 6, 5, 99, 10, 4, 8}));

System.out.println(countGreaterThanAverage(new int[]{1, 1, 1})); } }

What I got but cant figure out the 4th / 3rd test