Write a Python function aplit_halver() that, passed a lists, returns a two-tuple consisting of the list that is the first lulf of 1s and the list that is the second half of Is. If the length of 1 is odd, then there is one more element in the second component than in the first. Use slicing Note that is the integer division operator (e.g. 5//2 - 2) (My solutions has 3 lines.) The following are several example applications In [19] 1 split halves (10, 1, 2, 3, 4, 5, 6, 7) Out[19) (0, 1, 2, 3, 4, 5, 6, 71) In 2011 split_halve (0, 1, 2, 3, 4, 5, 6, 7, 8)) Out (2011 (10. 1. 2. 3. 4. 5. 6. 7. 81) In 12111 split_halves (10 Out (211 (10) In 12211 wpiss_halves (11) Out (22) (01.11)