Write a short bash script to count the number of blank lines in a file or from stdin. you are not allowed to use the -c/--count option of grep in your solution or awk/sed unfortunately.

how it'll function: numblank [-q] [FILE...] the option -q (for quiet): if supplied, counts are not printed out; exit status alone is used to return info (see below); must be the first command-line argument to numblank if supplied; 2 [FILE...] indicates that one or more file names/paths may be supplied, but all are optional:

if no FILE arguments are supplied, the program is to read from standard input, and print out a single line containing only the count of the number of blank lines found

if a single FILE argument is given, the program is to print a single line containing only a count of the number of blank lines found; if multiple FILE arguments are supplied, counts for each file are to be printed on

some example calls:

numblank foo1 foo2 foo3 foo1:5 foo2:0 foo3:23 numblank -q foo (no output) cat foo | numblank 12 Please be specific about what is unclear, it seems very specific right now.