Write a similar question as at ove using a map function. First, try to replicate exactly...

 

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Write a similar question as at ove using a map function. First, try to replicate exactly the same doctests (Make sure you understand why it is not possible). Now write a function that takes a list of integers and another positive integer, factor. Your function should return a list, where each element from a given list has a given factor, and if that's not the case, replace it with None. Requirement: You cannot NOT use loops and list comprehension for this question. Instead, you must use lambda and map functions. There are no restrictions on the number of lines, but our solution is one line. def practice 3(1st, factor): ****** >>> practice_3([1,3,5], 3) [None, 3, None] >>> practice_3([1,3,5], 1) [1, 3, 5] >>> practice_3([], 10) [] >>> practice 3([1,3,4,6,5], 2) [None, None, 4, 6, None] |||||| Write a similar question as at ove using a map function. First, try to replicate exactly the same doctests (Make sure you understand why it is not possible). Now write a function that takes a list of integers and another positive integer, factor. Your function should return a list, where each element from a given list has a given factor, and if that's not the case, replace it with None. Requirement: You cannot NOT use loops and list comprehension for this question. Instead, you must use lambda and map functions. There are no restrictions on the number of lines, but our solution is one line. def practice 3(1st, factor): ****** >>> practice_3([1,3,5], 3) [None, 3, None] >>> practice_3([1,3,5], 1) [1, 3, 5] >>> practice_3([], 10) [] >>> practice 3([1,3,4,6,5], 2) [None, None, 4, 6, None] ||||||

Answer rating: 100% (QA)

ANSWER You can achieve this using the map function and a lambda function as follows def practice3ls... View the full answer