Write an ARM assembly language which accepts an integer and returns a string which is the hexadecimal representation of the integer.

The signature of the routine is: char * int2hex( int conv ) ;

The input is a 32 bit integer. The output is a pointer to a character string of the format 0Xdddddddd. Do not suppress leading zeroes.

The C program is:

#include #include

extern char * int2hex( int convert ) ;

int main( int argc, char * argv[] ) { int convert = 1194684 ; char * result ; result = int2hex( convert ) ; printf( "Integer to hex string: %s ", result ) ; }

A string in C is terminated by a null byte (a byte of zero). You will need to use the shift instructions. You need to separate the integer into 4 bit sections each representing the individual hex digits. These need to be turned into printable characters. You need to adjust the resulting values for the digits A-F. Use the strb instruction and an auto increment of 1 since you are storing bytes into memory. Use the malloc library routine to obtain space for the character string (11 bytes: 2 for 0x, 8 for the hex digits, and one for the null byte).