Write an equivalent double integral with the order of integration reversed. Show your work!

${\displaystyle \underset{0}{\overset{1}{}}}{\displaystyle \underset{0}{\overset{ta{n}^{-1}x}{}}}dydx$

A$){\displaystyle \underset{0}{\overset{\frac{}{4}}{}}}{\displaystyle \underset{tany}{\overset{\frac{}{2}}{}}}dxdy$

B$){\displaystyle \underset{0}{\overset{\frac{}{4}}{}}}{\displaystyle \underset{tany}{\overset{1}{}}}dxdy$

C$){\displaystyle \underset{0}{\overset{\frac{}{4}}{}}}{\displaystyle \underset{ta{n}^{-1}y}{\overset{1}{}}}dxdy$

D$){\displaystyle \underset{0}{\overset{\frac{}{4}}{}}}{\displaystyle \underset{ta{n}^{-1}y}{\overset{\frac{}{2}}{}}}dxdy$

E$){\displaystyle \underset{0}{\overset{\frac{}{2}}{}}}{\displaystyle \underset{ta{n}^{-1}y}{\overset{tany}{}}}dxdy$