Write an LC-3 assembly language program to read in a

two-digit decimal number whose digits add up to less than

10 and display the sum of those digits in the next line.

Sample execution

Please enter a two-digit decimal number > 27

The sum of the digits = 9

This is what I have so far. I'm probably approaching this wrong.

.ORIG x3000

LEA R0,PROMPT1 ; Displays first prompt.

PUTS

; First number

GETC ; Reads char

ST R0,CHAR ; Safe keeps char.

LD R0,CHAR ; Reload char

OUT ; Output a character to the monitor

; Second Number

GETC ; Reads char

ST R1,CHAR2 ; Safe keeps char.

LD R1,CHAR2 ; Reload char

OUT ; Output a character to the monitor

; Next Line

LD R0,CRLF ; Executes new line.

OUT ; Writes char

LEA R0,PROMPT2 ; Displays second prompt.

PUTS

LD R0,CRLF ; Executes new line.

OUT ; Writes char

LD R0,CHAR ; Reload first char

LD R1,CHAR ; Reload second char

LD R4,NEG30

ADD R0,R0,R1

ADD R0,R0,R4

OUT ; Displays uppercase.

HALT

;************ Data area*******************************

PROMPT1 .STRINGZ "Enter a two-digit decimal number> "

PROMPT2 .STRINGZ "The value of the two numbers added togeter> "

CHAR .BLKW 2

CHAR2 .BLKW 1

CHAR3 .BLKW 1

NEG30 .FILL #-48

CRLF .FILL #10

.END