WRITE ARM ASSEMBLY CODE for the equaivelnt c++ code

For each of the following C++-like pseudo code segments, write equivalent ARM assembly language instructions.

a)) if (r1

r2 = r2 + r1; }

r2 = r2 + 4;

b)) if (r1

r3 = r3 + 50;

else

r3 = r3 r2;

c)). if (r1 == r2)

r1 = r1 + 10;

else if (r1 > r2)

r1 = r1 - 10;

else if (r1

r1 = r1 + 20;

else

r1 = 100 r1;

d)). switch (r0) {

case 0: r5=r5+r1;

// Note that there is no break here

case 1: r5=r5+r2;

break

case 2: r5=r5+r3;

break;

default: r5=r5*r4+r6; }

e)) for (r4 = 0; r4

r1 = r1 + r4;

r2 = r2 - 1; }

f)). while (r4

r1 = r1 - 2;

r2 = 40 - r2;

r4 = r4 + 1;

}

g)) do {

r1 = r1 - 2;

r2 = 40 r2;

r4 = r4 + 1;

} while ( r4

Question IL 170 markala For each of the following C++-like pseudo code segments, write equivalent ARM assembly language instructions .. if (r 32) 1 -r1 - 10 else if (r1 13) r1 - rl 20 else r1 = 100 - 11: d. switch () case 0:5 15 + 1 // Note that there is no break here case 1: 5 - 35 22: 15 - 15. 13: break NAME default: break; 5 - 15 r. 26 1 e. for (4 = 04 32) 1 -r1 - 10 else if (r1 13) r1 - rl 20 else r1 = 100 - 11: d. switch () case 0:5 15 + 1 // Note that there is no break here case 1: 5 - 35 22: 15 - 15. 13: break NAME default: break; 5 - 15 r. 26 1 e. for (4 = 04