Write in MIPS the following

1) Ask for user input

2) Iterate over each character

3) Print each character to the screen

Here is my code:

###################################

#

# Simple Integer Calculator

#

#

#

####################################

.data

buffer: .space 20

str1: .asciiz "Enter in the problem: "

str2: .asciiz "The result is: "

.text

main:

la $a0, str1 # Load and print string asking for string

li $v0, 4

syscall

li $v0, 8 # take in input

la $a0, buffer # load byte space into address

li $a1, 20 # allot the byte space for string

move $t0, $a0 # save string to t0

syscall

la $a0, str2 # load and print "The result is" string

li $v0, 4

syscall

# la $t0, str # la means load address (so we load the address of str into $t0)

li $t1, 0 # $t1 is the counter. set it to 0

la $t3, 61 # 43 is ASCII of '+' in DEC

countChr:

lb $t2, 0($t0) # Load the first byte from address in $t0

beqz $t2, end # if $t2 == 0 then go to label end

addi $t1, $t1, 1

bne $t2, $t3, proceed # branch if symbol equals 43 (+)

move $t4, $t1 # save the position

proceed:

addi $t0, $t0,1 # else increment the address

j countChr # finally loop

end:

li $v0,1 # print $t0

move $a0,$t4

syscall

#la $a0, buffer # reload byte space to primary address

#move $a0, $t0 # primary address = t0 address (load pointer)

#li $v0, 4 # print string

#syscall

li $v0, 10 # end program

syscall