Write out the memory map for the following code, providing all values at the end of execution. How many total bytes does this code declare for variables?

{ *b=a-(char)i; b--; *j=i+5; j++; }

double d[3],*e; int i,*j; char a,*b,c[3]; i=3;

j=&i; d[0]=4.2; e=&(d[1]); *(e-1)=1.5; e[1]=2.3; for (i=0; i<5; i++) c[i%3]=(char)(*j+i); b=&a; *b=c[2];