Question: Write the equation in exponential form. log, 512=9 The equation in exponential form is XWrite the equation in exponential form. log =-1 6 1,000,000 The

 Write the equation in exponential form. log, 512=9 The equation inexponential form is XWrite the equation in exponential form. log =-1 61,000,000 The equation in exponential form is XWrite the equation in exponentialform. In 1 =0 The equation in exponential form is e X5Write the equation in logarithmic form. 92 = 81 The equation inlogarithmic form is Olog XWrite the equation in logarithmic form. The equationin logarithmic form is e OInGraph the function. y = log; xPlot four points and an asymptote. Then click on the graph icon.9- HTH X -9 -7 -6 -5 -4 -3 -2 -1 1234 6Use the function below to answer the following questions. y =log3 (x -3) +4 (a) Use transformations of the graph of y= log; x to graph the given function. (b) Write the domainand range in interval notation. (c) Write an equation of the asymptote.Part: 0 / 3 Part 1 of 3 (a) Use transformations ofthe graph of y = log; x to graph the given function.15-1 V 10-4 X 5 5-1 -15 -10 -5 10 15 5-1-10- -15-1Write the domain in interval notation. f(x) = log (3 -x)The domain is (0,0) [0,0] (0,0] [0,0) OVO - OO XWrite thedomain in interval notation. Write your answers as integers or simplified fractions

Write the equation in exponential form. log, 512=9 The equation in exponential form is XWrite the equation in exponential form. log =-1 6 1,000,000 The equation in exponential form is XWrite the equation in exponential form. In 1 =0 The equation in exponential form is e X 5Write the equation in logarithmic form. 92 = 81 The equation in logarithmic form is Olog XWrite the equation in logarithmic form. The equation in logarithmic form is e OInGraph the function. y = log; x Plot four points and an asymptote. Then click on the graph icon. 9- HTH X -9 -7 -6 -5 -4 -3 -2 -1 123 4 6Use the function below to answer the following questions. y = log3 (x -3) +4 (a) Use transformations of the graph of y = log; x to graph the given function. (b) Write the domain and range in interval notation. (c) Write an equation of the asymptote. Part: 0 / 3 Part 1 of 3 (a) Use transformations of the graph of y = log; x to graph the given function. 15-1 V 10-4 X 5 5-1 -15 -10 -5 10 15 5-1 -10- -15-1Write the domain in interval notation. f(x) = log (3 -x) The domain is (0,0) [0,0] (0,0] [0,0) OVO - OO XWrite the domain in interval notation. Write your answers as integers or simplified fractions if necessary. h (x) = log, (7x+8) The domain is OVO (0,0) [0,0] (0,0] [0,0) OVO OO - OO X 5The intensities of earthquakes are measured with seismographs all over the world at different distances from the epicenter. Suppose that the intensity of a medium earthquake is originally reported as 10"" times /,. Later this value is revised as 10"" times . The local magnitude M (on the Richter scale) of an earthquake of intensity I is given by log Part: 0 / 3 Part 1 of 3 (a) Determine the magnitude of the earthquake using the original estimate for intensity. M = X 5Scientists use the pl scale to represent the level of acidity or alkalinity of a liquid. This is based on the molar concentration of hydrogen ions, [H*]. Since the values of [H*] vary over a large range, 1 x 10" mole per liter to 1 x 10 mole per liter (mol/L), a logarithmic scale is used to compute pl. The formula PH=- log H* ] represents the pl of a liquid as a function of its concentration of hydrogen ions, [H+]. The pH scale ranges from 0 to 14. Pure water is taken as neutral having a pH of 7. A pH less than 7 is acidic. A pH greater than 7 is alkaline (or basic). For this exercise, use the formula for pH. Round pH values to 1 decimal place. Lemon juice Wine Ammonia Bleach 10 11 12 13 14 pH 100 10-2 10-4 10-7 10-10 10-12 10-14 [H+ ] Water Acidic (neutral) Alkaline Sea water and milk of magnesia are both bases. Their [H+] values are 1.2 x 10 * mol/L and 4.3 x 10 mol/L, respectively. (a) Find the pl for sea water. (b) Find the pH for milk of magnesia. (c) Which substance is more basic? Part: 0 / 3

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