Write the first five terms of the recursively defined sequence.

$a_1=12,a_{k1}=\frac{1}{6}{a}_k^2$

Step $1$

Note that the kth term of the sequence is defined by $a_{k}1=\frac{1}{6}{a}^2.$

Let $a_1,a_2,a_3,a_4,$ and $a_5$ be the first five terms of the sequence.

Also note that $a_1=12.$

Substitute $k=1$ and $a_1=12$ in $a_{k1}=\frac{1}{6}{a}_k^2.$

Therefore.

$a_2=\frac{f}{a{a}^2{b}^2}=\frac{1}{6}({)}^2=$

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