Question: Write the in_order() function, which has a list of integers as a parameter, and returns True if the integers are sorted in descending order (in

Write the in_order() function, which has a list of integers as a parameter, and returns True if the integers are sorted in descending order (in order from high to low) or False otherwise. The program outputs "In descending order" if the list is sorted, or "Not in order" if the list is not sorted. Ex: If the list passed to the in_order() function is [5, 6, 7, 8, 3], then the function returns False and the program outputs: Not in order Ex: If the list passed to the in_order() function is [10, 8, 7, 6, 5], then the function returns True and the program outputs: In descending order Note: Use a for loop. DO NOT use sorted() or sort(). def in_order(nums): # Type your code here. if __name__ == '__main__': # Test out-of-order example nums1 = [5, 6, 7, 8, 3] if in_order(nums1): print('In descending order') else: print('Not in order') # Test in-order example nums2 = [10, 8, 7, 6, 5] if in_order(nums2): print('In descending order') else: print('Not in order')

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