Question: Write the MIPS code that adds a number in $ + 1 to the constant 1 0 0 and puts the result into $ +

Write the MIPS code that adds a number in $+1 to the constant 100 and puts
the result into $+3.
Assume the register mappings: a=$+0,b=$+1,c=$+2, tmp 1=$+3,+mp2=$+4,
tmp3=$+5
c=(a+3)**(b-2)+a;
Write MIPS code that does the following: F=A+(((B-C)+D)-E)
Assume: $+0 has A,$+1 has B,$+2 has C,$+3 has D,$+4 has E,$+5 has F
Write the MIPS code that adds a number in $ + 1

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