Write your answers (a)..(o) in the space provided below: 9. (15 points) Consider the following 8-bit floating point representation. For denomarlized numbers, actual exponent is 1 - bias. For nomarlized numbers, actual exponent is E-bias and the implied-1 rule applies. Fill in the table below. Type Sign Exponent Fraction E M Actual Exponent Value Increment 0 Denormalized actual exponent = 1 - bias 0 (a) (e)/512 0 0 0 0000 0000 0000 0001 0001 0001 0001 0001 0001 Normalized 0 001 010 011 000 001 010 011 100 101 110 111 (b)/512 (c)/512 (d)/512 (g)/512 (h)/512 (i)/512 (j)/512 (k)/512 (1)/512 (m)/512 (n)/512 0 actual exponent = E-bias (0)/512 0 0 0 0001 0 0001