$x=0$

$y=4$

$y=5$

$y=6$

$(b)$ Consider the IVP $d\frac{y}{d}x=x(y-5{)}^2-2,y(0)=y_0,$ where Can a solution $y(x)asx?$ Based $on$ the information $in$ part $(a),$ discuss. $y(x)$ can approach $asx$ approaches $.y(x)$ cannot approach $asx$ approaches $.$