${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{\sqrt[\phantom{2}]{x^2-16}}{x^3}dx$

$\frac{1}{8}se{c}^{-1}(\frac{x}{4})-\frac{\sqrt[\phantom{2}]{x^2-16}}{2x^2}C$

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$9.[-/0\mathrm{.}16$ Points$]$

SCALCET$97\mathrm{.}3\mathrm{.}025.0/100$ Submissions Used

Evaluate the integral. $($Remember to use absolute values where appropriate. Remember the constant of integration.$)$

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{\sqrt[\phantom{2}]{4x^2}}{x}dx$

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