Question: x 2 y ' ' + 4 x y ' + 2 y = l n ( x ) , subject to y ( 1

x2y''+4xy'+2y=ln(x), subject to y(1)=2 and y'(1)=0.
 x2y''+4xy'+2y=ln(x), subject to y(1)=2 and y'(1)=0.

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