$x{a}_x(t)=-(0\mathrm{.}0320\frac{m}{s^3})(15\mathrm{.}0s-t)t=0x=-14\mathrm{.}0m{v}_{0x}=8\mathrm{.}20\frac{m}{s}xt=10\mathrm{.}0sx=\frac{1}{28}$

Exercise $2\mathrm{.}50-$ Enhanced $-$ with Feedback

Part $A$

A small object moves along the $x-$axis with acceleration $a_x(t)=-(0\mathrm{.}0320\frac{m}{s^3})(15\mathrm{.}0s-t).Att=0$ the object $isatx=-14\mathrm{.}0m$ and has velocity $v_{0x}=8\mathrm{.}20\frac{m}{s}$

What $is$ the $x-$coordinate $of$ the object when $t=10\mathrm{.}0s?$

Express your answer with the appropriate units.

$x=$

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