Question: X' = AX where 5-3 A = , x(0) = | 3 1 , 1 2 [text {A. None B} B=left[begin{array}{I} 1+3+ 2+3+ end{array}
X' = AX where 5-3 A = , x(0) = | 3 1 , 1 2 \[\text {A. None B} B=\left[\begin{array}{I} 1+3+ \\2+3+ \end{array} ight] e^{2 t} \quad x=\left[\begin{array}{} 1-+ \\ 2-2 t \end{array} ight] e^{2+D} \quad x=\left[\begin{array}{I} 1-3+7 \\ 2-3+1 \end{array} ight] e^{2 t} x=\left[\begin{array} {1} 1+2 t \\2+2^{+t} \end{array} ight] e^{2+}"
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