X Determine the absolute extreme values of the function f(x) = m Absolute minimum value = |:| Absolute maximum value = |:| on the interval [2,7]. f(c ) = -0 [ 2, 7] fix) = d f(xc ) doc doc 8 2+3 ( 8x+ 3) doc - x d (8x+3 ) dac ( 82 + 3 ) 2 (8x+ 3) (11 - x (8) ( 82 +3 ) 2 1826 + 3 - 8x (8x +3 )2 fleel = 3 ( 82 + 3 ) 2 for critical Points f (x ) = 3 is undefined (8x + 31 2 fial = 0 at 8x+320 3 (82 -+ 3 ) 2 3 = 0 , this not Possible x = - 3 notin [2,7] So No Solution Put 20 = 2 in D Put x = 7 ino f ( 2 ) = 2 8 ( 2) +3 8( 7) +3 Absolute minimum value = ( 2, 2 ] AS Solute maximum Value = ( 7. Ja)we know that Extreme value lies on Critical Points that if f' (x ) =0 08 f lx ) = undefined and end Points on interval fa, b] find froid all the of lowest Value of fix) = absolute minimum highest Value of flat = absolute maximum Question No critical point , fix) = undefined at x = -3 8 which not Lie in [2,] So only extreme valued Wee at 2= 2,7