Question: (x-2) is a factor of the function f(x) = 2x3 + Ax + Bx + 18. When divided by (x 1), f(x) has a

 

(x-2) is a factor of the function f(x) = 2x3 + Ax

(x-2) is a factor of the function f(x) = 2x3 + Ax + Bx + 18. When divided by (x 1), f(x) has a remainder of 4. Find A and B; and factorize the function f(x). A = B = f(x) =

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Given that x2 is a factor of fx we can write fx x22x2 Cx D Expand... View full answer

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