X=6.517 E-3 MVx= 1.680 m/sAx=88.17 m/s ^2Y= 3.258 E-3 mVy= 0.840 m/sAy= 40.08 m/s

Look at all 6 graphs (you can maximize the windows to get a better look) to answer the following questions . 8 40 mis X = 6. 5 17 E -3 m VX= 1, 680 mis ax= 85.17 mls y= 3.258 E- 3mi ay = 40.08 1. At the top of the ant's trajectory (max height), what is its vertical velocity? vy = 6. 494 E-3 mis 2. At the top of the ant's trajectory (max height), what is its horizontal velocity vx = 1. 6 7 5-2 mis 3. When does the initial "launch" of the ant occur (from what to what time)? 0. 355 - 12. 413s 4. What is the horizontal launch velocity? 5. What is the vertical launch velocity? 6. Draw a vector diagram in the space below to show the horizontal and vertical launch velocities. Also draw the magnitude of the launch velocity vector