Question: y' (1) - If 2x + 3x + xy=1 and y(1)=-4, find y' (1) by implicit differentiation. -3 Thus an equation of the tangent
y' (1) - If 2x + 3x + xy=1 and y(1)=-4, find y' (1) by implicit differentiation. -3 Thus an equation of the tangent line to the graph at the point (1,-4) is
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2x23xxy1 Using the technique of implicit differentiation d2x23xxydxd1dx d2x2dxd3... View full answer
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