y (m) 0.6 0.4 r 02 P A 0 -0.2 Problem 4: A particle P moves...

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y (m) 0.6 0.4 r 02 P A 0 -0.2 Problem 4: A particle P moves along a curve defined by 72 = 2cos20 (r in meters, theta in rad). The angle 0 is given by 0 = 3t + 2t rad. When the particle is at the furthest right point of the curve, t = 0 and r = 2 m. For this time instant, give the vector velocity and vector acceleration of the particle. Hint: differentiate the equation of the curve to get expressions for and . Ans: p = (22) m/s; ap=(-1227+ 627) m/s 08 -0.4 -0.6 -0.8 H -1 -1 -0.5 0 0.5 2 x (m) y (m) 0.6 0.4 r 02 P A 0 -0.2 Problem 4: A particle P moves along a curve defined by 72 = 2cos20 (r in meters, theta in rad). The angle 0 is given by 0 = 3t + 2t rad. When the particle is at the furthest right point of the curve, t = 0 and r = 2 m. For this time instant, give the vector velocity and vector acceleration of the particle. Hint: differentiate the equation of the curve to get expressions for and . Ans: p = (22) m/s; ap=(-1227+ 627) m/s 08 -0.4 -0.6 -0.8 H -1 -1 -0.5 0 0.5 2 x (m)

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To find the vector velocity and vector acceleration of the particle when it is at the furthest right ... View the full answer