$y=sin(x^3+8)$

Find $\frac{dy}{dx}$

$\frac{dy}{dx}$

Type $sin(x)$ for $sin(x),cos(x)$ for $cos(x),$ and $soon.$

Use $x^{2}to$ square $x,x^{3}to$ cube $xsin(x)to$ square $sin(x).$

$Do$ NOT simplify your answer.