$y=\frac{x^4+2x-3}{x^2}$

$f(x)=(x^2)(e^{5x})$

$k(x)=(5x-1{)}^7$

Write the equation of the tangent line $($in $y=mx+6$ form$)$ to the function $f(x)=e^{2x}-3x+2$ when $x=0$

Find the values of $x$ where the tangent line$($s$)$ will be horizontal to $g(x)=3x^3-2x^2+1$