y$\text{'}ysinx=e^{cosx}$

$x^2\frac{du}{dx}2u=5$

Example $2\mathrm{.}19.$ Solve the initial value problem

$x^2\frac{dy}{dx}xy=x{y}^3,y(1)=1$

$x^2\frac{dy}{dx}xy=\frac{y^3}{x},y(1)=1$