Question: Y1=_____ OPTIMUM SOLUTION VALUE Z= Consider the following L.P. Model: 360 Maximize 320- Subject to: 280- Z = 20X+ 20X2 3X1 + 1X2 5300 1X,
Y1=_____
OPTIMUM SOLUTION VALUE Z=
Consider the following L.P. Model: 360 Maximize 320- Subject to: 280- Z = 20X+ 20X2 3X1 + 1X2 5300 1X, +1X2 200 1X4 S 100 1X, 250 X1, X220 (C1) (C2) (C3) (C4) 240- 200 X2 160- Constraints, C1, C2, C3 and C4 have been drawn on the graph to the right. 120- orn points for the feasible rea or a) Using the point drawing tool, locate all the the graph. 80- 40 0+ 0 40 80 120 240 280 320 360 160 200 X1 The optimum solution (using a corner point) is: X4 = (round your response to four decimal places)Step by Step Solution
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