Question: Yield Strength ( sigma y = 3 4 5 mathrm { MPa } ) Tensile Strength ( sigma

Yield Strength \(\sigma y=345\mathrm{MPa}\)
Tensile Strength \(\sigma \mathbf{\sigma}=414\mathrm{MPa}\)
Exercise 1
For the structure in the figure:
1. Find the reactions at the external supports and the normal force in the elastic element.
2. Find the dimension "\( b \)".\( b=(\mathrm{mm})\)
3. Calculate the deformation of the rod.
You will use the equations of Statics to find the Horizontal and Veritcal ractions at the external support.
After you have to use the equation which hels you find the Normal Force in the elastic element. This means that ycu have to make the sum of the moments towards the support point. The only unknown will be the tension on the elastic element.
After finding the tension at the elastic element you have to write the Condition of Strength. The mechanical characteristic of the materials are given. Is given as well the coefficient of safety. The dimension b will be in mm . It cannot be for example 3.7 mm . It has to be 4.
From 1 to 10 can be 1,2,3,4,5,6,7,8,9,10.
From 10 to 20 can be \(10,12,14,15,16,18,20\)
From 10 to 1000 it will be every 5 millimeters. And over 100 every 10.
Therefore, you cannot have a dimension 67 mm but either 65 or 70.
You cannot have a dimension 213 mm but either 210 or 220.
After you have to find the deformation of the rod in milimmeters. Should be a small number. Please be carefull when using the units.
\[
\Delta l=\frac{N l}{E A}
\]
\(\Delta l \)- Deformation of the Rod
N - Normal Force
1- Length of the Rod
E - Modul of Elasticity for the Rod Material
A - Aria of the Cross Section of the Rod
Yield Strength \ ( \ sigma y = 3 4 5 \ mathrm {

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Mechanical Engineering Questions!