You are studying three linked genes $($see map below$).$

R$-----5$cM$-----$F$-----18$cM$-----$K

A truebreeding $"$rf$"$ individual is mated with truebreeding $"$k$"$ individual. The resultant heterozygous individual is making gametes.$$ What is the probability of producing a $"$rfk$"$ gamete?$$

Question $3$ options:

a$)$

$(0\mathrm{.}05)$

b$)$

$(0\mathrm{.}18)$

c$)$

$(0\mathrm{.}05*0\mathrm{.}18)$

d$)$

$(0\mathrm{.}95*0\mathrm{.}18)$

e$)$

$(0\mathrm{.}05*0\mathrm{.}82)$

f$)$

$(0\mathrm{.}95*0\mathrm{.}82)$

g$)$

$1/2(0\mathrm{.}05*0\mathrm{.}18)$

h$)$

$1/2(0\mathrm{.}05*0\mathrm{.}82)$

i$)$

$1/2(0\mathrm{.}95*0\mathrm{.}18)$

j$)$

$1/2(0\mathrm{.}95*0\mathrm{.}82)$

k$)$

$(8!/1!7!)(0\mathrm{.}95)^1(0\mathrm{.}18)^7$

l$)$

$(8!/1!7!)(0\mathrm{.}05)^1(0\mathrm{.}82)^7$

m$)$

$(8!/7!1!)(0\mathrm{.}95)^7(0\mathrm{.}18)^1$

n$)$

$(8!/7!1!)(0\mathrm{.}95)^7(0\mathrm{.}18)^1$

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Question $4(1$ point$)$

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You are studying three linked genes $($see map below$).$

R$-----5$cM$-----$F$-----18$cM$-----$K

A truebreeding $"$rf$"$ individual is mated with truebreeding $"$k$"$ individual. The resultant heterozygous is test crossed.$$ What is the probability of producing a $"$rfk$"$ INDIVIDUAL?$$

Question $4$ options:

a$)$

$(0\mathrm{.}05)(0\mathrm{.}05)$

b$)$

$(0\mathrm{.}18)(0\mathrm{.}18)$

c$)$

$(0\mathrm{.}05*0\mathrm{.}18)*(0\mathrm{.}05*0\mathrm{.}18)$

d$)$

$(0\mathrm{.}95*0\mathrm{.}18)*(0\mathrm{.}95*0\mathrm{.}18)$

e$)$

$(0\mathrm{.}05*0\mathrm{.}82)*(0\mathrm{.}05*0\mathrm{.}82)$

f$)$

$(0\mathrm{.}95*0\mathrm{.}82)*(0\mathrm{.}95*0\mathrm{.}82)$

g$)$

$1/2(0\mathrm{.}05*0\mathrm{.}18)$

h$)$

$1/2(0\mathrm{.}05*0\mathrm{.}82)$

i$)$

$1/2(0\mathrm{.}95*0\mathrm{.}18)$

j$)$

$1/2(0\mathrm{.}95*0\mathrm{.}82)$

k$)$

$(8!/1!7!)(0\mathrm{.}05)^1(0\mathrm{.}82)^7$