Question: You are to create a C program which fills an integer array with integers and then you are to cast it as a char *

You are to create a C program which fills an integer array with integers and then you are to cast it as a "char * and print it out the string relating the "char * The output of the string should be your first and last name with proper capitalization, spacing and punctuation.

The 'C' language has a 32 bit (4 byte ) data word structure. We will be using ASCII (single byte values) for characters You are to fill in the 4 bytes of each integer with characters from your name. This means you need to have 4 characters in each 'C' integer word. Please note that INTEL architectures are little Endian.

The idea, is to have your program allocate a chunk of data via and array of integers. You are then to place the correct integers into the array (4 bytes at a time), and then end the final integer with a '0', because C uses the null character to indicate end of string.

Your program should have structure similar to:

main() {

int A[100]; char *S;

A[0]=XXXX; A[1]=YYYY;

...

A[n]=0; -- because C strings are terminated with NULL

...

printf("My name is %s ",S);

}

in c

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