Question: You have a signed 4 - bit number A and an unsigned 4 - bit number B in 2 s complement number system. You know

You have a signed 4-bit number A and an unsigned 4-bit number B in 2s
complement number system. You know that A is always non-positive, e.g., zero
or negative. Now, design the (absolute) magnitude comparator by modifying the
magnitude comparator you have studied from the class. Please modify the circuit
below to perform the (absolute) magnitude comparator. Note you do not need to
consider the case that A is a positive number
Questions (100 points)
Please solve the following questions.
(1) Prove the equality of the left and right terms of the following equations. (10
points)
((A*B)+(A*C)+(B*C))*(()/(bar)(A*B*C))=(A*B(*)/(b)ar (C))+(A*C(*)/(b)ar (B))+(B*C(*)/(b)ar (A))
(2) Prove the equality of the left and right terms of the following equations. Note A^(')
is not(A).(10 points)
(3) Draw the gate level schematic of the right term in (2). Assume you already have
A^('),B^('),C^(')(no need to draw an inverter).(10 points)
(4) Draw the right term of (2) to have the equivalent delay of the inverter whose
NMOS and PMOS are sized 1 and 2, respectively. Assume that the signal
arrival time is in the order of B->C-> A.(10 points)
(Total: 40 points)

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